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kurs:histogramm_gehaltsverteilung

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select i, coalesce(lpad('*', count(s), '*'), ' ') from (             
  select trunc(salary, -3) s from 
    employees 
) stat right join 
   (select level*1000 i from dual connect by level <= 25) r
on r.i = stat.s
group by i
order by i

resultat:

1000 2000 3000 4000 * 5000 * 6000 7000 * 8000 * 9000 10000 11000 12000 * 13000 14000 * 15000 16000 17000 18000 19000 20000 21000 22000 23000 24000 * 25000

kurs/histogramm_gehaltsverteilung.1367928209.txt.gz · Last modified: 2014/09/10 21:22 (external edit)