This is an old revision of the document!
/*select first_name, last_name, trunc(salary*1.276711235) from employees
select sum(salary),
min(salary),
max(salary),
avg(salary),
median(salary),
stddev(salary)
from employees
*/
-- desc employees
select count(department_id) from employees;
select avg(commission_pct),
sum(commission_pct),
count(commission_pct),
count(*),
sum(commission_pct)/count(*) from employees
select
department_name,
trunc(avg(salary)),
sum(salary) susa
from employees e join departments d on
d.department_id = e.department_id
group by
department_name
-- having sum(salary) > 20000
order by susa
select 12 + null from dual;